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18u^2-1=34
We move all terms to the left:
18u^2-1-(34)=0
We add all the numbers together, and all the variables
18u^2-35=0
a = 18; b = 0; c = -35;
Δ = b2-4ac
Δ = 02-4·18·(-35)
Δ = 2520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2520}=\sqrt{36*70}=\sqrt{36}*\sqrt{70}=6\sqrt{70}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{70}}{2*18}=\frac{0-6\sqrt{70}}{36} =-\frac{6\sqrt{70}}{36} =-\frac{\sqrt{70}}{6} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{70}}{2*18}=\frac{0+6\sqrt{70}}{36} =\frac{6\sqrt{70}}{36} =\frac{\sqrt{70}}{6} $
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